0=-36x^2+144

Solution for 0=-36x^2+144 equation:

0=-36x^2+144

We move all terms to the left:

0-(-36x^2+144)=0

We add all the numbers together, and all the variables

-(-36x^2+144)=0

We get rid of parentheses

36x^2-144=0

a = 36; b = 0; c = -144;
Δ = b2-4ac
Δ = 02-4·36·(-144)
Δ = 20736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20736}=144$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-144}{2*36}=\frac{-144}{72}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+144}{2*36}=\frac{144}{72}
=2
$